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Solution :

We know, `DeltaG^(Theta) =- 2.303 RT log_(10)K_(c)` <br> Given, `K_(c) =2xx10^(5),T = 298 K,R = 8.314 J K^(-1)mol^(-1)` <br> Thus, form the above equation, <br> `DeltaG^(Theta) =- 2.303 xx 8.314 xx 298 log 2xx10^(5) = 8.588 kJ`